x/2(3-x)-x^2/7(x-3)^2

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Solution for x/2(3-x)-x^2/7(x-3)^2 equation: 


x in (-oo:+oo)

(x/2)*(3-x)-(((x^2)/7)*(x-3)^2) = 0

1/2*x*(3-x)-1*1/7*x^2*(x-3)^2 = 0

1/2*x*(3-x)-1*1/7*x^2*(x-3)^2 = 0

6/7*x^3-1/7*x^4-25/14*x^2+3/2*x = 0

6/7*x^3-1/7*x^4-25/14*x^2+3/2*x = 0

x*(6/7*x^2-1/7*x^3-25/14*x+3/2) = 0

(-1/7)*x^3+(6/7)*x^2+(-25/14)*x+3/2 = 0

(-1/7)*x^3+(6/7)*x^2+(-25/14)*x+3/2 = 0 // * 0

{ 1, -1, 3, -3, 7, -7, 21, -21 }

1

x = 1

12*x^2-2*x^3-25*x+21 = 6

1

-1

x = -1

12*x^2-2*x^3-25*x+21 = 60

-1

3

x = 3

12*x^2-2*x^3-25*x+21 = 0

3

x-3

6*x-2*x^2-7

12*x^2-2*x^3-25*x+21

x-3

2*x^3-6*x^2

6*x^2-25*x+21

18*x-6*x^2

21-7*x

7*x-21

0

6*x-2*x^2-7 = 0

DELTA = 6^2-(-7*(-2)*4)

DELTA = -20

DELTA < 0

x in { 3} 

x*(x-3) = 0

x*(x-3) = 0

( x-3 )

x-3 = 0 // + 3

x = 3

( x )

x = 0

x in { 3, 0 }

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